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blackpen
redpen
math for fun
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1+2+3+4+5+6+7+... = 3/16
In Math Problems
Zorméar
Mar 18, 2019
what if not
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a question
In Math Problems
Zorméar
Mar 18, 2019
Hi there let's say A = n+(n+1)+...+(n+k) = (n+(n+k))(k+1)/2 B = (n+k+1)+...+(n+k+m) = (n+k+1+n+k+m)(m)/2 (these are just basic sum formulas, arithmetic series) The left hand side is just A/B, so the final result is (n+(n+k))/((n+k+1)+(n+k+m)) * (k+1)/m I think
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