I was playing around with some repeated logarithms for complex values and noticed that it always converged to the same value. A little bit of googling got this result, https://math.stackexchange.com/a/255727/458712. I'm a math novice, and I have enjoyed the videos on the Lambert W function. Is there any way to put this explanation into more layman's terms?
Math problem would be: z0 = i
z1 = ln(z0)
.
.
zn = ln(z(n-1))
Per the attached SE site, this converges to .3181315052−1.337235701i . The explanation in the link is a bit over my head, and could use some help getting to a better understanding.
You delivered such an impressive piece to read, giving every subject enlightenment for us to gain information. Thanks for sharing such information with us due to which my several concepts have been cleared. Traductores en Kissimmee
Wow, What an Outstanding post. I found this too much informatics. It is what I was seeking for. I would like to recommend you that please keep sharing such type of info.If possible, Thanks. service internet providers edmonton
I am thankful to you for sharing this plethora of useful information. I found this resource utmost beneficial for me. Thanks a lot for hard work. สล็อตหมุน วงล้อ ฟรี แล้วได้เงิน
It is truly a well-researched content and excellent wording. I got so engaged in this material that I couldn’t wait reading. I am impressed with your work and skill. Thanks. dna extractor
Wow, excellent post. I'd like to draft like this too - taking time and real hard work to make a great article. This post has encouraged me to write some posts that I am going to write soon. listesi
It is my first visit to your blog, and I am very impressed with the articles that you serve. Give adequate knowledge for me. Thank you for sharing useful material. I will be back for the more great post. 77 evoสล็อต
Great job here on _______ I read a lot of blog posts, but I never heard a topic like this. I Love this topic you made about the blogger's bucket list. Very resourceful. สล็อต joker ฝาก ถอน ไม่มี ขั้น ต่ำ
Please continue this great work and I look forward to more of your awesome blog posts. PVC ramen en deuren Antwerpen
Im no expert, but I believe you just made an excellent point. You certainly fully understand what youre speaking about, and I can truly get behind that. Thuisbatterij zonnepanelen kopen
Great job for publishing such a beneficial web site. Your web log isn’t only useful but it is additionally really creative too. Vakantiewoning Limburg België
Pretty good post. I just stumbled upon your blog and wanted to say that I have really enjoyed reading your blog posts. Any way I'll be subscribing to your feed and I hope you post again soon. Big thanks for the useful info. Zonnepanelen vergelijken
I am impressed. I don't think Ive met anyone who knows as much about this subject as you do. You are truly well informed and very intelligent. You wrote something that people could understand and made the subject intriguing for everyone. Really, great blog you have got here. Zonnepanelen installateur gezocht
I appreciate this article for the well-researched content and excellent wording. I got so interested in this material that I couldn’t stop reading. Your blog is really impressive. seo
Succeed! It could be one of the most useful blogs we have ever come across on the subject. Excellent info! I’m also an expert in this topic so I can understand your effort very well. Thanks for the huge help. Ramen en deuren kopen
Thanks for an interesting blog. What else may I get that sort of info written in such a perfect approach? I have an undertaking that I am just now operating on, and I have been on the lookout for such info. Zoekmachine optimalisatie seo
Great content material and great layout. Your website deserves all of the positive feedback it’s been getting. Tuinontwerpen
An fascinating discussion is value comment. I think that it is best to write extra on this matter, it won’t be a taboo topic however generally people are not enough to talk on such topics. To the next. Cheers Terrasoverkapping op maat
This is because the problem can be formulated as follows:
ln ln ln ln ..... ln x = u
=> e^(ln ln ln ln ..... ln x) = e^u
=> u=e^u
=> u * e^(-u) = 1
=> -u * e^(-u) = -1
=> LambertW(-u * e^(-u)) = LambertW(-1)
=> -u=LambertW(-1)
=> u = -LambertW(-1) which is equal to the constant you have found
The limit is always the same, regardless the initial x you may choose!!!!!