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Omair Siddique
May 22, 2019

(Real Number)^(Complex Number)

Evaluate 2^i

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伍逸朗
May 23, 2019

cos(ln2)+isin(ln2)

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Omair Siddique
May 27, 2019

Please explain the procedure

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Thrith
May 30, 2019

@Omair Siddique We know that e^ln(x)=x (I used e because I can't type logs with bases, but it works for any number, not just e), so we can rewrite the equation as the following:


2^i=(e^ln(2))^i=e^(i*ln(2))


We can use Euler's formula now, to determine the actual value. Euler's formula says that e^(ix)=cos(x)+i*sin(x).


e^(i*ln(2))=cos(ln(2))+i*sin(ln(2))=0.769+0.638i


Someone correct me if I'm wrong.

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