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May 12, 2021

# please help to find out the limit as n-tends to > infinity
for the (e) option here

please help to find out the limit as n-tends to > infinity
for the (e) option here

2 answers2 replies

You asked for part(e) but your arrow points to part (d). Anyway, here is part (e).

Divide all 4 terms by sqrt(n). This will get you:

{ (n + 1/n)^.5 + 1} / (n + 1/n)^.25 - 1}

It's all over now as the numerator takes off faster than the denominator. So the expression ----> infinity.

If that's not enough rigour for you then let

m =( n + 1/n)^.25As

n ---> infinitythenm also ---> infinitySo now we have: { m^2 + 1} /{ m-1} as m ---> infinity and you can take it from there.

@Ian Fowler big thanks bro

@Krishna Goswami You are very welcome.

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