How do we integrate x/(3-x)(3+2x) with, ofc, respect to x?

Partial fractions decomposition is 1/3(1/(3-x)+1/(3+2x)), use u-substitution with u1=3-x and u2=3+2x, then integrate into natural log.

If I have misinterpreted your notation, please let me know, and I will attempt another explanation.

Partial fractions decomposition is 1/3(1/(3-x)+1/(3+2x)), use u-substitution with u1=3-x and u2=3+2x, then integrate into natural log.

If I have misinterpreted your notation, please let me know, and I will attempt another explanation.