*What is a so that LIM(x->inf) ( (x+a)/(x-a) ) ^ x = e *? (Which I saw him present today, 7-30-22, on youtube)

I argue straightaway that a = 1/2. We know that **1) **LIM(x->inf) ( (1 + (1/x))^x ) = e.

But 1 + (1/x) can also be written as **(x+1)/x**. So, if we let **y = x + 1/2 **above, and use **a = 1/2**:

then LIM(x->inf) ( (x+1/2)/(x-1/2) ) ^ x becomes **LIM(y->inf) ( (y+1)/y ) ^ (y-1/2)**.

As y->inf, y-1/2 becomes y. This is just 1) with 'y' instead of 'x'.

How do I submit this to bprp channel, of which I'm a member? - 0over0 (Jack Ritter)

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