Limit[((1 + x)^(2/x) - e^2 (1 - Log (1 + x)))/x, x - 0]

Is the answer e^2 or 0, me and my boi have two results.

Question

Limit[((1 + x)^(2/x) - e^2 (1 - Log (1 + x)))/x, x -> 0]&#010;&#010;Is the answer e^2 or 0, me and my boi have two results.

Ian Fowler · Accepted Answer

I can't remember how many times I walked away from this but I kept coming back. I went around in circles for a long time.

I finally plotted a graph of [(1+x)^(1/x) - e]/x and there it was staring me in the face : -e/2 on the y-axis. times 2e to get -e^2. Combine with the first one to get 0.

Your intuitive way, I think, is more elegant. But here is the good old fashioned brute force method. Thanks again. Ian

Franck Ray · Answer

Oh! Thank ya for your work!  I'll just put your old fashioned method into my pocket, if you don't mind XD. And sorry for the late reply, something's wrong with my VPN, took me a while to fix it. Anyway, look forward to discussing more math problems with ya!! ;-)

Ian Fowler · Answer

I think you have nailed it in your photo. Good work. Sorry for the mess up on my first attempt. Ian

Franck Ray · Answer

I think we cannot plug 0 as x into the expression, cuz it's 'x->0'.Anyway here's my way, will it work? I hate limit questions...

anbowang48 · Answer

@Ian Fowler yup

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math for fun

Limit[((1 + x)^(2/x) - e^2 (1 - Log (1 + x)))/x, x -> 0] Is the answer e^2 or 0, me and my boi have two results.