## math for fun

To see this working, head to your live site.

Edited: Jul 26, 2020

# Limit[((1 + x)^(2/x) - e^2 (1 - Log (1 + x)))/x, x -> 0]
Is the answer e^2 or 0, me and my boi have two results.

Limit[((1 + x)^(2/x) - e^2 (1 - Log (1 + x)))/x, x -> 0]
Is the answer e^2 or 0, me and my boi have two results.

6 answers2 replies

8 Comments

I can't remember how many times I walked away from this but I kept coming back. I went around in circles for a long time.

I finally plotted a graph of [(1+x)^(1/x) - e]/x and there it was staring me in the face : -e/2 on the y-axis. times 2e to get -e^2. Combine with the first one to get 0.

Your intuitive way, I think, is more elegant. But here is the good old fashioned brute force method. Thanks again. Ian

I think you have nailed it in your photo. Good work. Sorry for the mess up on my first attempt. Ian

I think we cannot plug 0 as x into the expression, cuz it's 'x->0'.

Anyway here's my way, will it work? I hate limit questions...

@Ian Fowler yup

@Ian Fowler In 2, are you sure it is in indeterminate form? plug 0 into the expression you had in 2, (1-ln(1+0))/0=(1-ln(1))/0=1/0 therefore, that bit also diverges

Limit[((1 + x)^(2/x) - e^2 (1 - Log (1 + x)))/x, x -> 0]