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i and e

in Math Problems

In two of your videos you prove i^i = e^(-Pi/2) and the ith root of i, I^(1/i) = e^(Pi/2).

When I multiply i^i by i^(1/i) I get i.

But when I multiple the representations e^(-Pi/2) and e^(Pi/2) I get e.

So, does i = e? Where have I gone wrong?

4 comments

4 Comments

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Oct 18, 2021

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DL Bourke

Jan 10, 2020

Woops, its i^(i+(1I))

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i and e