How do you integrate: 2log(2.6x-6) with log base 10

Convert log (base 10) to a natural log

log(a) = ln(a) / ln(10)

The 10 can be replaced by any positive number b.

log a(base b) = ln(a) / ln(b)

========================

y = log a (baseb)

====> a = b^y

====> ln(a) = ln(b^y)

====> ln(a) = y*ln(b)

====? y = ln(a) / ln(b)

Convert log (base 10) to a natural log

log(a) = ln(a) / ln(10)

The 10 can be replaced by any positive number b.

log a(base b) = ln(a) / ln(b)

========================

y = log a (baseb)

====> a = b^y

====> ln(a) = ln(b^y)

====> ln(a) = y*ln(b)

====? y = ln(a) / ln(b)