How do you integrate: 2log(2.6x-6) with log base 10
Convert log (base 10) to a natural log
log(a) = ln(a) / ln(10)
The 10 can be replaced by any positive number b.
log a(base b) = ln(a) / ln(b)
========================
y = log a (baseb)
====> a = b^y
====> ln(a) = ln(b^y)
====> ln(a) = y*ln(b)
====? y = ln(a) / ln(b)
Convert log (base 10) to a natural log
log(a) = ln(a) / ln(10)
The 10 can be replaced by any positive number b.
log a(base b) = ln(a) / ln(b)
========================
y = log a (baseb)
====> a = b^y
====> ln(a) = ln(b^y)
====> ln(a) = y*ln(b)
====? y = ln(a) / ln(b)