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Mellophi
Sep 6, 2020

Find number of paths possible



2 answers1 reply
0
1
Ian Fowler
Sep 6, 2020  ·  Edited: Sep 7, 2020

I ripped this one off pretty fast. Can someone check the logic please. I'm not sure. My brain is fried after the derangements.

vertex # of choices

A 3

B 3

C 1

D 3

E 3

F 1

G 2

H 2

(4^2)(3^2)(2^2) = 576



Mellophi
Sep 6, 2020

why not 4 choices from D?

0
1
Ian Fowler
Sep 7, 2020  ·  Edited: Sep 7, 2020

You are correct of course- and E as well! good eye.