Ian FowlerMay 13, 2020 · Edited: May 13, 2020I started with integration by parts since int[ln(x)]dx = x[ln(x)-1] but didn't get very far. Nice problem. Thanks.

Charlie DrinnanMay 14, 2020Ultimately did it this way, but was after many attempts to make it work by integration by parts

Ian FowlerMay 14, 2020 · Edited: May 14, 2020@Charlie Drinnan I nearly **** (am I allowed to do that here?) my pants when I sawe^(x^2+2x+1) * (x+1). :)And when you move x^-1 in the denom and you see ln(x)/x with ln^2(x) in the exponent - same thing,

Charlie DrinnanMay 14, 2020Ha. Yeah, same boat. But, that eureka moment when you figure out the ln^2(x) insight is really nice.

Mason WilliamSep 13, 2021I’m excited to uncover this page. I need to to thank you for ones time for this particularly fantastic read !! I definitely really liked every part of it and i also have you saved to fav to look at new information in your site. Profit League

I started with integration by parts since int[ln(x)]dx = x[ln(x)-1] but didn't get very far. Nice problem. Thanks.

Yeah. Seems like integration by parts would work.

Ultimately did it this way, but was after many attempts to make it work by integration by parts

@Charlie Drinnan I nearly **** (am I allowed to do that here?) my pants when I saw

e^(x^2+2x+1) * (x+1). :)

And when you move x^-1 in the denom and you see ln(x)/x with ln^2(x) in the exponent - same thing,

Ha. Yeah, same boat. But, that eureka moment when you figure out the ln^2(x) insight is really nice.

I’m excited to uncover this page. I need to to thank you for ones time for this particularly fantastic read !! I definitely really liked every part of it and i also have you saved to fav to look at new information in your site.

Profit League