OC and OB are radii of the circle that means they are equal. So we get x at angle C then you use Sum of angles in all triangles to get x which will be equal to 60.
x + x + x = 180.

it's 60 degrees because all equilateral triangles have angles of 60 degrees since all the

angles are equal, x + y + z= 180 deg, since <x is equal to <y which is equal to <z, then we could say <x + <x + <x = 180 degrees, so, 3<x = 180 degrees, divide both sides by 3, thus <x = 60 degrees

aren't lines OC and OB radii of the semi - circle? which means they are equal just like in an isoceles triangle the sides are equal which makes the angles equal right?

60 degree

Correct. Proof?

OC and OB are radii of the circle that means they are equal. So we get x at angle C then you use Sum of angles in all triangles to get x which will be equal to 60. x + x + x = 180.

that's how i see it. your welcome

Oh yeah. what an idiot i am :(

Nah bro mistakes happen and that's what makes math interesting and fun!

I've been in your place multiple times and that's why we have a community to help each other out :)

it's 60 degrees because all equilateral triangles have angles of 60 degrees since all the

angles are equal, x + y + z= 180 deg, since <x is equal to <y which is equal to <z, then we could say <x + <x + <x = 180 degrees, so, 3<x = 180 degrees, divide both sides by 3, thus <x = 60 degrees

why does OC=OB imply x is at angle C???

aren't lines OC and OB radii of the semi - circle? which means they are equal just like in an isoceles triangle the sides are equal which makes the angles equal right?