I can try. It's called synthetic division. It is a shorthand notation for doing long division which I personally prefer. So before attempting an explanation I need to know where to start. If you are familiar with the factor theorem ( and I assume you are ) and how it relates to zeros of a polynomial then that will shorten my attempt considerably.

I have something on paper (step by step) which will attempt to explain why his method works rather than just go through the paces. It is long. It is also a very good example of why "online" learning really falls far, far short when trying to achieve understanding of why a short cut works rather than memorize the recipe. Let me clean it up and see what I can present.

If I could sit down with you one-on-one at a table the explanation would be so much easier for both you and me. There is "no substitute" for teaching in a live setting and I am no fan of "on-line" learning when the concepts involve a lot more than just handing over trivial information. To me it is just a cop-out that saves boards of education a ton of money. And you can take that to the bank. Get back to you soon.

Totally agree with you, I miss my teacher... I tried to simplify the equation with an euclidean division of the cubic fonction by y-1. Here's my work (sorry if it's not very clear) but I find -y^2+y+1 and he finds y^2-y-1. C

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I can try. It's called synthetic division. It is a shorthand notation for doing long division which I personally prefer. So before attempting an explanation I need to know where to start. If you are familiar with the factor theorem ( and I assume you are ) and how it relates to zeros of a polynomial then that will shorten my attempt considerably.

Oh yeah I remember seing it in class (thx for helping me)

I have something on paper (step by step) which will attempt to explain why his method works rather than just go through the paces. It is long. It is also a very good example of why "online" learning really falls far, far short when trying to achieve understanding of why a short cut works rather than memorize the recipe. Let me clean it up and see what I can present.

If I could sit down with you one-on-one at a table the explanation would be so much easier for both you and me. There is "no substitute" for teaching in a live setting and

I am no fanof "on-line" learning when the concepts involve a lot more than just handing over trivial information. To me it is just a cop-out that saves boards of education a ton of money. And you can take that to the bank. Get back to you soon.Totally agree with you, I miss my teacher... I tried to simplify the equation with an euclidean division of the cubic fonction by y-1. Here's my work (sorry if it's not very clear) but I find -y^2+y+1 and he finds y^2-y-1. C

an we say it's the same thing ?

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