Furkan Özdemir
Mar 16, 2019

a question

while n , k , m are integers :


(n + (n+1) + (n+2) .... + (n + k))/ ((n + k + 1) + (n + k + 2) ..... + (n + k + m) = (n + (n + k)) / ((n + k + 1) + (n + k + m )




CAN YOU PROVE THIS ?


(NOTE: I AM NOT SURE THIS IS ALREADY PROVED OR NOT)

2 comments
Zorméar
Mar 18, 2019

Hi there


let's say

A = n+(n+1)+...+(n+k) = (n+(n+k))(k+1)/2

B = (n+k+1)+...+(n+k+m) = (n+k+1+n+k+m)(m)/2 (these are just basic sum formulas, arithmetic series)


The left hand side is just A/B, so the final result is (n+(n+k))/((n+k+1)+(n+k+m)) * (k+1)/m

I think