"Given the function y = x^4 - (m+1)x^2 + m. Find the value(s) of m such that the area defined by the curve y and the x-axis that is above the x-axis is equal to the total area defined by the curve y and the x-axis that is below the x-axis." (Sorry if this is a bit wordy).

I still a bit confused. Do you mean the area between the roots?

Since this a "w shaped" function for all m>-1 and the bump in the middle flattens as m ----> -1. Fort m = -1 there is no more bump and the curve has a loosely phrased "parabola-like shape" and at that point, this question doesn't make sense to me.

So I have to assume for this question you do mean the area between the roots, which are always 1, -1, sqrt(m), -sqrt(m). Also m>0 in order to have any area above the x-axis.

When m > 1 the +/-root m roots are on the outside of the 1,-1 roots

When 0 < m < 1 the +/- root m roots are between the 1,-1 roots.

So 2 answers:

m > 1: m = 5

0 < m < 1: m = 1/5

Yes, the area between the roots. And by the way, m > 1 is clearly the same as m = 5. So which one? And it seems like 0 < m < 1 does not work, I checked on Desmos.

You have to break it into 2 cases:

1)

0 < m < 1where the sqrt(m) root < the 1 root, then the bounds of integration are from0---->1The answer is m = 1/5 and the right side of the photo clearly proves it.

2)

m > 1where the sqrt(m) root > the 1 root, then bounds of integration are from0 ----> sqrt(m)The answer is m = 5. Solution is on the lower right. I couldn't be bothered busting it up into 2 integrals, 0---->1 and 1------> sqrt(5), to verify that the areas are negatives of each other. I'll leave that to you.

And by the way, m > 1 is clearly the same as m = 5. So which one?The

case restrictionis m > 1 which leads to the solution m = 5.So the question "which one?" doesn't make any sense.

This is reason #1 why doing it yourself is superior than relying on Desmos - which is clearly wrong.

At any rate, it is a good problem. Thanks.

Oh yeah, sorry for the stupid question. And thanks for the good solution.