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Anh Thái Huỳnh
Mar 05, 2019
(1+i) +(1+i) ^2 +(1+i) ^3+...+(1+i) ^2017=S
in Math Problems
S=?
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maxxkiller
Mar 05, 2019
S = sqrt(2)^2018 -1 + 1i
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Math Nerd 1729
Jan 27, 2020
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maxxkiller
Isn't sqrt(2)^2018 just 2^1009?
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S = sqrt(2)^2018 -1 + 1i